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Ten cards numbered 11, 12, 13, 14, ., 20 are placed in a box. A card is removed at random from the box. Find the probability that the number on the card is either even or divisible by 3.



A. 2 / 5
B. 3 / 5
C. 4 / 5
D. 3 / 20

This question is part of Lesson 6 Quiz - Addition of Probabilities and Mutually Exclusive Events
Asked by Enxian, Last updated: Dec 05, 2017

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1 Answer

John Smith

John Smith

Answered on Sep 29, 2016

3 / 5

Let E be the event that the number of the card is even and T be the event that the number is divisible by 3. E and T are NOT mutually exclusive events. E or T = {12, 14, 15, 16, 18, 20} P(E or T) = n(E or T) / n(S) = 6/10 = 3/5
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