What is the initial concentration of A if the concentration of A is 0.023 M after 48.0 hours?

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John Smith

Answered Sep 27, 2016

1. 0.11 M

Solving: t1/2 = 21.7 hr = 0.693/ k k = 0.693/21.7hr ln[A]0/[A] = kt ln[A]0/0.023M = 0.693/21.7hr 48.0hr = 1.533 ln[A]0/0.023M =1.533 [A]0/0.023M=4.63 [A]0 = 4.63 0.023M = 0.11 M

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