How many hosts per network, and total networks do you get once subnetted?

Agreed. 6 of 8 available bits needed to create 64 subnets(2^6 = 64). This leaves 2 bitsfor hosts which would only allow for 4 ip addresses(2^2 =4). Cant use first or last, so 2 hosts and 64 networks (assuming you can use the zero networks)

2 Hosts and 64 Subnets
193.103.20.0 Need 50 Networks 128 64 32 16 8 4 2 1 0 0 1 1 0 0 1 0 = 50 in binary Need to borrow 6 bits for # of Networks New Subnet Mask = 255.255.255.11111100 (252) or /30 ^ Increment = 4 2^6 = # of Networks = 64 2^2-2 = # of Hosts per Network = 2 First 5 IP Ranges 193.103.20.0 - 193.103.20.3 20.4 20.7 20.8 20.11 20.12 20.15 20.16 20.19