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Give the possible phenotypes and the percentage chance for each in the dihybrid cross between two pea plants that are heterozygous in producing smooth, yellow peas. The smooth allele is dominate over the wrinkled allele, and yellow is dominant over green.



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Biology 2nd Quarter
Asked by Austin, Last updated: Mar 06, 2020

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John Smith

John Smith

Answered Sep 08, 2016

Since the parents are both heterozygous in each allele, their genotypes aressyy. there are 4 possible gametes: sy, sy, sy, sy. the resulting punnett square, then, is: sy sy sy sysy ssyy ssyy ssyy ssyysy ssyy ssyy ssyy ssyysy ssyy ssyy ssyy ssyysy ssyy ssyy ssyy ssyysmooth, yellow peas (genotypes ssyy, ssyy, ssyy, ssyy) 9 of 16 or 56.25 %smooth, green peas (genotypes ssyy, ssyy) 3 of 16 or 18.75 %wrinkled, yellow peas (genotypes ssyy, ssyy) 3 of 16 or 18.75 %wrinkled, green peas (genotype ssyy) 1 of 16 or 6.25 %
 

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