How many millliters of a 3% (w/v) will be necessary to make 6oz of a 1:200 solution?

Asked by Wyatt Williams, Last updated: Apr 14, 2024

+ Answer

Request

0
Follow

Share

Answer Anonymously
Answer Later

Copy Link

3 Answers

O. Bickis, Corporate employee, MBA, Stockton

Answered Mar 31, 2020

The correct answer is option A – 30 ML

To calculate how many millliters of a 3% (w/v) will be necessary to make 6oz of a 1:200 solution. We use this formular:

C1V1 = C2V2
C1 = concentration of original solution
C2 = concentration of diluted solution
V1= volume of original solution
V2 = volume of diluted solution
1/200 = 0.005
0.005 x 100 = 0.5%
x oz of 3% + (6 - x) oz water (0% solute) = 6 oz of 0.5%
3x + 0(6-x) = 6x 0.5%
3x + 0 = 3
3x =3
x= 1
1 oz = 29.6mL
Approx. 30 ML

G. Horace, Content Developer, Chicago

Answered Jan 30, 2019

3% x 1/200= 0.015% C1V1=C2V2 C1= original concentration =3% C2 =concentration of diluted solution (0.015%) V2=volume of diluted solution=6oz (3) (V1)=(0.015) 6oz (3) (V1)=(0.015) (6oz) /3=0.030 oz 0.030 x (29.5mL/1fl oz) =0.89 mL The making of a solution of a given percentage strength is a simple matter where both the substance and solvent are weighed, the preparation of a definite volume of a solution of a given percentage of strength is the way to calculate how many milliliters and the solution.