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For the second-order reaction below, the rate constant of the reaction is 9.4 × 10–3 M–1s–1. How long (in seconds) is required to decrease the concentration of A from 2.16 M to 0.40 M? 2A → B rate = k[2 



A. 2.0 × 10^1 s
B. 7.8 × 10^1 s
C. 1.8 × 10^2 s
D. 1.9 × 10^2 s
E. 2.2 × 10^2 s

This question is part of CHEM 2425
Asked by Ochiengj, Last updated: Feb 27, 2020

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1 Answer

John Smith

John Smith

Answered May 19, 2017

2.2 × 10^2 s

Solving: 1/[A] 1/[A]0 = kt 1/0.40 1/2.16 = 9.4 103 t T = 216 = 2.2 102 s
 

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