What is the empirical formula for a compound that contains 37.69% Na - ProProfs Discuss
Topics
Products
Follow Us:

What is the empirical formula for a compound that contains 37.69% Na and 62.31 % Fluorine?



A. NaF3
B. Na2F
C. NaF
D. NaF2

This question is part of Percent Composition of chemical compounds
Asked by Kwchiro, Last updated: Apr 01, 2020

+ Answer
Request

1 Answer

John Smith

John Smith

Answered Jan 29, 2017

NaF2

Change percent to grams: 37.69 g of Na and 62.31 g of Fluorine. Empirical formula is the simplest whole number ratio of moles. Change grams to moles (divide by molar mass) Na: 37.69 / 22.99 g = 1.639 moles F : 62.31 g/19.00 g = 3.279 moles Divide each by 1.639: Na 1 and F 2 = NaF2
 

Search for Google images
Select a recommended image
Upload from your computer
Search for Google images
Select a recommended image
Upload from your computer
Search for Google images
Select a recommended image
Upload from your computer

Email Sent
We have sent an email to your address "" with instructions to reset your password.