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In electrical logging the measured resistivity of flushed zone is 19.2 ohm-m , the resistivity of mud filtrate is 1.33 ohm-m and computed value of residual oil saturation in flushed zone is 20%.
Answered Dec 13, 2018
(1-0.80)^2= a/porosity^m * 1.33/19.2
F=a/porosity^m
F=9.248
Formulause : Sxo^n=a/ porosity^m* rmf / rxo
sxo= water saturation in flushed zone
sxo= 1- oil saturation in flushed zone
oil sturation + water stauration= 1
1-0.20= 0.80
Answered Sep 11, 2018
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