How far away must (s)he sit? - ProProfs Discuss

# How far away must (s)he sit? On one side of a see-saw, there is a person with a weight of 600N. He is sitting 3m away from the pivot. On the other side, is a person weighing 450N.

A. 2m
B. 4m
C. 6m
D. 3.5m
E. 3m

This question is part of Physics - Moments Test
Asked by Ben_oneill, Last updated: Apr 07, 2020

#### O. Bickis

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O. Bickis, Corporate employee, MBA, Stockton

The answer to this is letter B. 4 meters. The reason for this is based on the weights of the people who are using the see-saw. You should remember that the person on one side is 600 N while the person on the other side is 450N.

This means that without knowing where to properly sit, the heavier person will just stay on the ground without any effort. The lighter person should sit 4 meters away from the pivot point so that everything will be balanced. In order to compute, you can use this equation: 600N x 3m = 1800Nm. 1800Nm/450N =4m.

The other person must sit 4m away from the pivot point in order to balance out the see saw

#### Milkah

Milkah

Clockwise moments =anticlockwise moments

600N×3m=1800Nm therefore

_×450=1800

1800Nm÷450N=4m

#### mariahossam.nes

Mariahossam.nes

4m
because 600 x 3 = 1800
1800/450 = 4

M= f x d
450g=600x3
450g=1800
g=1800/450
g=4m

#### John Smith

John Smith

4m

Moment = distance from pivot x force = 600N x 3 = 1800Nm Therefore, on the other side, the see-saw must have a moment of 1800Nm 1800/450 = 4