The correct answer to this question is B, 43.2 g. The mass of the glucose in one mole is calculated and then compared. First, one must identify that there are : 12 H = 1.0079g x 12 =12.0948 g , 6 C = 12.011g x 6 = 72.066 g , and 6 O = 15.9994g x 6 = 95.9964 g .

Once we have these figures, we must add and find the mass of glucose in one mole. One mole glucose is 180.157 g. Knowing that we can find our answer using the equation, 0.240 mol glucose x (180.157 g glucose / 1 mol glucose), which equals 43.238 g glucose