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Calcium carbonate decomposes to calcium oxide and carbon dioxide. CaCO3(s) CaO(s) + CO2(g) ΔH0 = 179 kJ The equilibrium constant for this reaction is 9.7 × 1024 at 298 K. What is the equilibrium constant at 575 K? (R = 8.31 J/molK)





A. 7.5 × 10^-16
B. 1.3 × 10^-8
C. 1.4 × 10^-38
D. 1.3 × 10^-15
E. 1.0 * 10^-23

This question is part of CHEM 2425
Asked by Ochiengj, Last updated: Mar 28, 2020

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ochiengj

Ochiengj

Answered Feb 22, 2018

1.3 10^-8
 

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