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How many Networks will be created after you subnet? Also, what is the first usable IP Address in the Second Network range? Your company wants to utilize the private Class C IP Address of 192.168.1.0. You are tasked with Subnetting the Address to get the most networks with at least 30 Hosts per Subnet.



A. 8 Networks, First usable from second Network range = 192.168.1.33
B. 3 Networks, First usable from second Network range = 192.168.2.33
C. 5 Networks, First usable from second Network range = 192.168.1.1
D. 8 Networks, First usable from second Network range = 192.168.1.1

This question is part of CCNA Subnetting Quiz
Asked by AP_Jake, Last updated: Jul 29, 2020

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5 Answers

erijosh

Erijosh

Answered Aug 30, 2018

A.

8 Networks, First usable from second Network range = 192.168.1.33

 

tarekscorpio

Tarekscorpio

Answered Nov 12, 2017

A is the right answer because the 32 time 8 is 256 exactly :)

 

Michael_

Michael_

Answered Jul 20, 2017

Agree with both. 2^5=32 - 2 = 30 hosts per network. Network block size is 32. Second network .32 to .63

Second network, first useable host id is 33 (bit for 32 reservedin subnet mask not allowed all 0's)

 

pinstrypsoldier

Pinstrypsoldier

Answered Mar 24, 2017

Agreed.

2^5=32. Means we need to LEAVE 5 bits at least out of the possible 8 for hosts. This leaves 3 for network. 2^3=8networks. 32 addresses per network.

First network .0 to .31 first useable .1
Second network .32 to .63 first useable .33
 

John Smith

John Smith

Answered Oct 13, 2016

8 Networks, First usable from second Network range = 192.168.1.33

192.168.1.0 Need 30 Hosts per Network 128 64 32 16 8 4 2 1 0 0 0 1 1 1 1 0 = 30 in binary Need to save 5 bits for # of Hosts New Subnet Mask = 255.255.255.11100000 (224) or /27 ^ Increment = 32 2^3 = # of Networks = 8 2^5-2 = # of Hosts per Network = 30 First 5 IP Ranges 192.168.1.0 - 192.168.1.31 1.32 1.63 1.64 1.95 1.96 1.127 1.128 1.159
 

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