No your wrong

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This statement is false because momentum is a vector thus both magnitude and direction is taken into account.

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The answer to this is letter B. How was this conclusion reached? You need to check out the numbers used in the given as well as the direction used. According to the question, you are trying to get your dog to pull towards the direction that you want.

Since your dog pulled you 15 Newtons to the left and you tried to take control by doing 5 Newtons to the right, you can just subtract the numbers. 15-5 is equal to 10. Next, you need to check the direction. The rope is probably still leaning to the right since you were unable to pull it all the way to the left. This means that the answer to this question is 10 Newtons to the right which is letter B.

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The answer to this is A. The sum of their momentums is still the same with the sum of their momentums before they have collided with each other. There can be slight differences with their momentum depending on the sizes of the objects that will collide with each other. The speed of the objects will be a factor. The other factor has to be the size of the objects that will hit each other.

When a large object collides with a smaller object, expect that the larger object will have a higher momentum as compared to the smaller object. An object with a higher speed may be stopped when it hits a bigger object or the effect of the collision will be more felt by the object with higher speed.

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A collision is considered inelastic as long as the coefficient of restitution, e, is smaller than 1 or as long as kinetic energy is lost in the collision.

For two objects to stick together after a collision, it should be called a "perfectly inelastic collision", where e=0.

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The root square root of 2gh

1/2 mv2 = mgh

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Shouldn't it Bounce at a lesser height because it's an inelastic collision

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False

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One way to make complex math problems easier to understand is to relate them to everyday things. This can make the process of solving math problems more fun as well as more understandable. The mathematical explanation of impulse and momentum can be explained with the help of a scenario involving balls used to play pool.

If a 0.2 kilogram red cue ball rolling at 1.4 m/s elastically collides directly with a 0.2 kilogram 9 ball at rest the red cue ball can be expected to have a velocity of 0 m/s. Visualizing the balls helps make the problem much easier to understand.

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