Correct answer is C - the 2 objects are traveling at the same speed.

Neglecting air resistance, an object thrown up has the same speed as the second object thrown down from the top of a...Read More

Neglecting air resistance, an object thrown up has the same speed as the second object thrown down from the top of a...Read More

2 Answers

994 views
Avg velocity =Δx/Δt

= (50-30)m/(30-10)s

= 20m/20s

∴ Ave Velocity = 1m/s (None in the choices given.)

= (50-30)m/(30-10)s

= 20m/20s

∴ Ave Velocity = 1m/s (None in the choices given.)

4 Answers

475 views1 Answer

306 views
Units for acceleration should be expressed in m/s/s, not m/s.

5 Answers

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268 views1 Answer

255 views
Shouldn't the answer be 30 m/s because that is the average of the final and starting velocities

3 Answers

253 viewsHow come the displacement is 14.14? I mean i do not understand that! Can anyone tell me?

3 Answers

252 views
The velocity increases up to a time , and then becomes constant

For time t < t0 velocity of particle = constant positive value for time t > t0 velocity = slope...Read More

For time t < t0 velocity of particle = constant positive value for time t > t0 velocity = slope...Read More

1 Answer

251 views1 Answer

244 viewsOn 12s particle is at rest as y component of graph i.e. distance / displacement is constant . Hence , at this instant velocity remains zero.

3 Answers

243 views
It will have the same acceleration, both up the hill and down the hill.

1 Answer

240 views
1.25 m/s²

S = ut + &189 a t². With s= 40m, t = 4s and u = 7.5m/s, we get 40 = 7.54 + &189 a 44 ==> a =1.2m/s²

S = ut + &189 a t². With s= 40m, t = 4s and u = 7.5m/s, we get 40 = 7.54 + &189 a 44 ==> a =1.2m/s²

1 Answer

235 views1 Answer

234 views
Less than the speed it had when thrown upwards.

1 Answer

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