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Electrolysis Questions and Answers (Q&A)

M. Krasinski, Content Writer
Answered: Jan 29, 2019
The correct answer to this question is Pb²⁺ (l) + 2e⁻ → Pb (l) . Electrolysis is a technique that uses a direct electric current (DC) to create a chemical reaction that would...Read More

3 Answers

613 views
A. Cook, English Professor
Answered: Feb 28, 2019
The answer to this is letter B. Electrolysis is the process by which chemicals go through decomposition. You can use this formula for this purpose: 2H2O + 2e- → H2 + 2OH. Electrolysis is...Read More

2 Answers

440 views
LEE_Eling
Answered: Jul 12, 2020
A) anode, at which oxidation occurs

Positive electrode is called anode. Negative electrode is known as cathode.

1 Answer

331 views
Lucasjiang
Answered: Jul 12, 2020
The charges of the electrodes will be constant, hence the components will stay at the respective electrode

1 Answer

281 views
Nxr
Answered: Jul 12, 2020
Ions, reduced, oxidised

1 Answer

238 views
Prachiapj
Answered: Apr 17, 2017
This is wrong, the right answer for this should be (c) since ions are oxidized at the anode and reduced at the cathode.

5 Answers

233 views
John Smith
Answered: Jul 12, 2020
C) Anode: 2Br-(l) --> Br2(g) + 2e-; Cathode: Pb2+(l) + 2e- --> Pb(s)

1 Answer

231 views
John Adney
Answered: Mar 06, 2017
The carbon from the carbon anodes dissolve into the electrolyte and migrates to the cathode

2 Answers

224 views
John Smith
Answered: Jul 12, 2020
Using a larger diameter probe, decrease the timing and intensity, and avoid shallow insertions

1 Answer

219 views
Wyatt Williams
Answered: Jul 12, 2020
Ions, reduced, oxidised

1 Answer

211 views
Lucasjiang
Answered: Jul 12, 2020
So that electrostatic forces of attraction are overcome and the ions are mobile

1 Answer

211 views
LEE_Eling
Answered: Jul 12, 2020
D) Anode: positive terminal where oxidation occurs; Cathode: negative terminal where reduction occurs

1 Answer

209 views
John Smith
Answered: Jul 12, 2020
A

1 Answer

206 views
John Smith
Answered: Jul 12, 2020
If all other factors are constant, any ion lower in the electrochemical series gets discharged at the relevant electrode in preference to those above it. The table given below makes the point clear

1 Answer

205 views
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