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161 kilometers per hour

2 Answers

2 Answers

1 Answer

54 kmph

Let the speed of train A be SA = 45 kmph and that of train B be SB Then, time taken by train A = TA = 4 hours 48 minutes = 4 + 48/60 = 24/5 Time taken by train B = TB = 3 hours 20 minutes = 3 1/3 hours = 10/3 hours Using formula SA/SB = TB/TA 45/SB = 10/3 X 5/24 =...

Let the speed of train A be SA = 45 kmph and that of train B be SB Then, time taken by train A = TA = 4 hours 48 minutes = 4 + 48/60 = 24/5 Time taken by train B = TB = 3 hours 20 minutes = 3 1/3 hours = 10/3 hours Using formula SA/SB = TB/TA 45/SB = 10/3 X 5/24 =...

1 Answer

Distance = 5.5 km, displacement = 2.5 km

1 Answer

108

Length of train = 54 X 14 X 5/18 = 210 metres Time taken by the man to cross the stationary train = 210 X 18/ 7 X 5 = 6 X 18 = 108 seconds.

Length of train = 54 X 14 X 5/18 = 210 metres Time taken by the man to cross the stationary train = 210 X 18/ 7 X 5 = 6 X 18 = 108 seconds.

1 Answer

1 Answer

45-d

45 - d

45 -d

45- d

45 - d

45 -d

45- d

1 Answer

3

1 Answer

1 Answer

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