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Â€“1.03 Ã— 103 J/g

Solving: H/g =-(100.0 g+ 10.0g)×4.18 J/g0C ×(47.53 -25.18) 0C /10 .0 g = 1.03 × 103 J/g

Solving: H/g =-(100.0 g+ 10.0g)×4.18 J/g0C ×(47.53 -25.18) 0C /10 .0 g = 1.03 × 103 J/g

1 Answer

3.44 Ã— 10-ï€4 mol/LÎ‡s

Solving: 1.24 mol/Lhr = 1.24 mol/L3600s = 3.44 × 10-4 mol/Ls

Solving: 1.24 mol/Lhr = 1.24 mol/L3600s = 3.44 × 10-4 mol/Ls

1 Answer

65.0C

Solving: loses heat, so -4.94 kJ = 35.0 g ×4.18 J/ g 0C × (Tf 98.8 0C), Tf = 65.0 0C

Solving: loses heat, so -4.94 kJ = 35.0 g ×4.18 J/ g 0C × (Tf 98.8 0C), Tf = 65.0 0C

1 Answer

1.3 ã— 10^-8

1 Answer

18 s

Solving: ln[A]0/[A] = kt ln0.80/0.10 = 54 k k = 2.079/54 =0.0385 t1/2 =0.693/0.0385 = 18 s

Solving: ln[A]0/[A] = kt ln0.80/0.10 = 54 k k = 2.079/54 =0.0385 t1/2 =0.693/0.0385 = 18 s

1 Answer

1 and 3

1 Answer

1.8

Solving: K1 = SO3(g)2 / SO2(g)2 O2(g) K2 = NO2(g)2/ NO(g)2 O2(g) K = SO2(g) NO2(g) / NO(g) SO3(g) = (SO2(g)2 O2(g)/ SO3(g)2 ) × (SO3(g) NO(g)/ SO2(g) NO 2(g)) × ( NO2(g)2/ NO(g)2 O2(g)) = 1/ K1 × 1/K × K2 K2 = K2 / K1 =16 /4.8 = 3.33 K = 1.8

Solving: K1 = SO3(g)2 / SO2(g)2 O2(g) K2 = NO2(g)2/ NO(g)2 O2(g) K = SO2(g) NO2(g) / NO(g) SO3(g) = (SO2(g)2 O2(g)/ SO3(g)2 ) × (SO3(g) NO(g)/ SO2(g) NO 2(g)) × ( NO2(g)2/ NO(g)2 O2(g)) = 1/ K1 × 1/K × K2 K2 = K2 / K1 =16 /4.8 = 3.33 K = 1.8

1 Answer

Â€“0.360 mol/LÎ‡s

1 Answer

2.24 0C

Solving: 10.0 g× 333 J/g = -25.0 g ×4.18 J/g 0C × (T 35) 0C, 104.5 T = 3657.5 3330, T = 3.13 0C

Solving: 10.0 g× 333 J/g = -25.0 g ×4.18 J/g 0C × (T 35) 0C, 104.5 T = 3657.5 3330, T = 3.13 0C

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