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The total number of possible outcomes is equal to the number of element in the sample space. The sample space S = {2, 4, 6, 8, 10, 12, 14, 16, 18, 20} and the number of elements in S = 10.

The total number of possible outcomes is equal to the number of element in the sample space. The sample space S = {2, 4, 6, 8, 10, 12, 14, 16, 18, 20} and the number of elements in S = 10.

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1 / 2

Let E be the event that x + y is odd. Using the possibility diagram, we can easily see that n(S) = 16 and n(E) = 8. Therefore, P(E) = 8 / 16 = 1 / 2

Let E be the event that x + y is odd. Using the possibility diagram, we can easily see that n(S) = 16 and n(E) = 8. Therefore, P(E) = 8 / 16 = 1 / 2

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Answer updated on: 28 Nov 2017

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S = {2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12}

S = {2,3,4,5,6,7,8,9,10,11,12}

Possible outcomes of the experiment = 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12. S = {2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12} Note: 1 is not a possible outcome as the minimum sum of the values of both dice = 1 + 1 = 2

S = {2,3,4,5,6,7,8,9,10,11,12}

Possible outcomes of the experiment = 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12. S = {2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12} Note: 1 is not a possible outcome as the minimum sum of the values of both dice = 1 + 1 = 2

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