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Answer updated on: 12 Feb 2020
54 kmphLet the speed of train A be SA = 45 kmph and that of train B be SB
Then, time taken by train A = TA
= 4 hours 48 minutes = 4 + 48/60 = 24/5
Time taken by train B = TB
= 3 hours 20 minutes = 3 1/3 hours = 10/3 hours
Using formula SA/SB = TB/TA
45/SB = 10/3 X 5/24 = 25/36 = 5/6
SB = 45 X 6/5 = 54 kmph.
Answer updated on: 12 Feb 2020
108Length of train = 54 X 14 X 5/18 = 210 metres
Time taken by the man to cross the stationary train = 210 X 18/ 7 X 5 = 6 X 18
= 108 seconds.
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