Answers
Answer updated on: 12 Feb 2020
199.2.1.224 - 199.2.1.255199.2.1.0 Need 5 Networks
128 64 32 16 8 4 2 1
0 0 0 0 0 0 1 0 1 = 5 in binary
Need to borrow 3 bits for of Networks
New Subnet Mask = 255.255.255.11100000 (224) or /27
^ Increment = 32
2^3 = of Networks = 8
2^5-2 = of Hosts per Network = 30
All 8 IP Ranges
199.2.1.0 - 199.2.1.31
1.32 1.63
1.64 1.95
1.96 1.127
1.128 1.159
1.160 ...
Answer updated on: 12 Feb 2020
2 Hosts and 64 Subnets193.103.20.0 Need 50 Networks
128 64 32 16 8 4 2 1
0 0 1 1 0 0 1 0 = 50 in binary
Need to borrow 6 bits for of Networks
New Subnet Mask = 255.255.255.11111100 (252) or /30
^ Increment = 4
2^6 = of Networks = 64
2^2-2 = of Hosts per Network = 2
First 5 IP Ranges
193.103.20.0 - 193.103.20.3
20.4 20.7
20.8 20.11
20.12 ...
Answer updated on: 12 Feb 2020
Yes203.10.93.0 Need 30 Networks
128 64 32 16 8 4 2 1
0 0 0 1 1 1 1 0 = 30 in binary
Borrow 5 Bits for of Networks
New Subnet Mask = 255.255.255.11111000 (248) or /29
^ Increment = 8
2^5 = of Networks = 32
2^3-2 = of Hosts per Network = 6
First 5 IP Ranges
223.10.93.0 - 223.10.93.7
93.8 93.15
93.16 93.23
93.24 93.31
93.32
Answer updated on: 12 Feb 2020
Subnet Mask 255.255.255.128 with an Increment of 128130.13.0.0 Need 500 Networks
128 64 32 16 8 4 2 1 . 128 64 32 16 8 4 2 1
0 0 0 0 0 0 0 1 . 1 1 1 1 0 1 0 0 = 500 in binary
Need to borrow 9 bits for of Networks
New Subnet Mask = 255.255.11111111.10000000 (255.128) or /25
^ Increment = 128
2^9 = of Networks = 512
2^7-2 = of Hosts per Network = 126
First 5 IP ...
Answer updated on: 12 Feb 2020
2 Hosts and 64 Subnets193.103.20.0 Need 50 Networks
128 64 32 16 8 4 2 1
0 0 1 1 0 0 1 0 = 50 in binary
Need to borrow 6 bits for of Networks
New Subnet Mask = 255.255.255.11111100 (252) or /30
^ Increment = 4
2^6 = of Networks = 64
2^2-2 = of Hosts per Network = 2
First 5 IP Ranges
193.103.20.0 - 193.103.20.3
20.4 20.7
20.8 20.11
20.12 ...
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