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# Basic Concepts Of Permutations And Combinations

20 Questions
• 1.
is evaluated as
• A.

43

• B.

34

• C.

24

• D.

None of these

• 2.
is equal to
• A.

1

• B.

24

• C.

0

• D.

None of these

• 3.
7! is equal to
• A.

5040

• B.

4050

• C.

5050

• D.

None of these

• 4.
0! is a symbol equal to
• A.

0

• B.

1

• C.

Infinity

• D.

None of these

• 5.
In nPr ,n is always
• A.

An integer

• B.

A fraction

• C.

A positive integer

• D.

None of these

• 6.
In nPr, the restriction is  Options: A.n > r B. C. D. None of these
• A.

A

• B.

B

• C.

C

• D.

D

• 7.
In  nPr =n (n-1) (n-2) ........................ (n-r-1), the number of factor is
• A.

N

• B.

R-1

• C.

N-r

• D.

R

• 8.
nPr can also written as Options: A. B. C. D.None of these
• A.

A

• B.

B

• C.

C

• D.

D

• 9.
If nP4 = 12 x nP2, then is equal to
• A.

-1

• B.

6

• C.

5

• D.

None of these

• 10.
If . nP3: nP2 =3:1, then n is equal to
• A.

7

• B.

4

• C.

5

• D.

None of these

• 11.
m+nP2 = 56, m-nP2 = 30 then
• A.

M =6, n = 2

• B.

M = 7, n= 1

• C.

M=4,n=4

• D.

None of these

• 12.
If 5Pr= 60, then the value of r is
• A.

3

• B.

2

• C.

4

• D.

None of these

• 13.
If n1+n2 P2 = 132, n1-n2P2 = 30 then,
• A.

N1=6,n2=6

• B.

N1=10,n2=2

• C.

N1=9,n2=3

• D.

None of these

• 14.
The number of ways the letters of the word COMPUTER can be rearranged is
• A.

40320

• B.

40319

• C.

40318

• D.

None of these

• 15.
The number of arrangements of the letters in the word FAILURE, so that vowels are always! coming together is
• A.

576

• B.

575

• C.

570

• D.

None of these

• 16.
10 examination papers are arranged in such a way that the best and worst papers never come together. The number of arrangements is
• A.

9[8]!

• B.

10!

• C.

8[9]!

• D.

None of these

• 17.
N articles are arranged in such a way that 2 particular articles never come together. The number of such arrangements is
• A.

(n-2)n-1!

• B.

(n-1)n-2!

• C.

N!

• D.

None of these

• 18.
If 12 school teams are participating in a quiz contest, then the number of ways the first, second and third positions may be won is
• A.

1230

• B.

1320

• C.

3210

• D.

None of these

• 19.
The sum of all 4 digit number containing the digits 2, 4, 6, 8, without repetitions is
• A.

133330

• B.

122220

• C.

213330

• D.

133320

• 20.
The number of 4 digit numbers greater than 5000 can be formed out of the digits 3, 4, 5, 6 and 7 (no. digit is repeated). The number of such is
• A.

72

• B.

27

• C.

70

• D.

None of these

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