Basic Concepts Of Permutations And Combinations

20 Questions  I  By Sweetsalman123
Please take the quiz to rate it.

 Basic Concepts Of Permutations And Combinations

  
Changes are done, please start the quiz.


Questions and Answers

Removing question excerpt is a premium feature

Upgrade and get a lot more done!
1.   is equal to Options: A. B. C. D.None of these
A.
B.
C.
D.
2.  If n cr-1 = 56, = 28 and n cr+1 = 8, then r is equal to
A.
B.
C.
D.
3.  The number of ways in which 6 men can be arranged in a row so that the particular 3 men sit together,is Options: A. B. C. D.None of these
A.
B.
C.
D.
4.  The number of arrangements of the letters in the word FAILURE, so that vowels are always! coming together is
A.
B.
C.
D.
5.   is equal to Options: A. B. C. D.None of these
A.
B.
C.
D.
6.  The number of words that can be made by rearranging the letters of the word APURNA so that vowels and consonants appear alternate is
A.
B.
C.
D.
7.  A question paper contains 6 questions, each having an alternative.The number of ways an examine can answer one or more questions is
A.
B.
C.
D.
8.  The ways of selecting 4 letters from the word EXAMINATION is
A.
B.
C.
D.
9.  In a group of boys the number of arrangement of 4 boys is 12 times the number of arrangements of 2 boys.The number boys in the group is
A.
B.
C.
D.
10.  The Supreme Court has given a 6 to 3 decision upholding a lower court; the number of mays it can give a majority decision reversing the lower court is
A.
B.
C.
D.
11.  The value of 
A.
B.
C.
D.
12.  Eight guests have to be seated 4 on each side of a long rectangular table. 2 particular guests desire to sit on one side of the table and 3 on the other side. The number of ways in which the sitting arrangements can be made is
A.
B.
C.
D.
13.  The number of arrangement of the letters of the word COMMERCE is
A.
B.
C.
D.
14.  7! is equal to
A.
B.
C.
D.
15.  If the letters word 'Daughter' are to be arranged so that vowels occupy the odd places, then number of different words are
A.
B.
C.
D.
16.  At an election there are 5 candidates and 3 members are to be elected. A voter is entitled to vote for any number of candidates not greater than the number to be elected. The number of ways a voter choose to vote is
A.
B.
C.
D.
17.  If  =336 and =56,then n and r  will be
A.
B.
C.
D.
18.  The number of ways in which the letters of the word DOGMATIC can be arranged is
A.
B.
C.
D.
19.  The number of ways in which 9 things can be divided into twice groups containing 2, 3, and 4 things respectively is
A.
B.
C.
D.
20.  If n1+n2 P2 = 132, n1-n2P2 = 30 then,  
A.
B.
C.
D.
Back to top

Removing ad is a premium feature

Upgrade and get a lot more done!
Take Another Quiz
We have sent an email with your new password.