We have sent an email with your new password.

Close this window

Basic Concepts Of Permutations And Combinations

20 Questions  I  By Sweetsalman123
Basic Concepts Of Permutations And Combinations

  
Changes are done, please start the quiz.


Question Excerpt

Removing question excerpt is a premium feature

Upgrade and get a lot more done!
1.  There are 5 speakers A,B,C,D,E.The number of ways in which A will speak always before B is Options:  A.24 B.«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mn»4«/mn»«mo»!«/mo»«mo»§#215;«/mo»«mn»2«/mn»«mo»!«/mo»«/math» C.5! D.None of these
A.
B.
C.
D.
2.  8 points are marked on the circumference of a circle. The number of chords obtained by joining these in pairs is
A.
B.
C.
D.
3.  10 examination papers are arranged in such a way that the best and worst papers never come together. The number of arrangements is
A.
B.
C.
D.
4.  The value of «math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«msub»«msub»«mn»12«/mn»«mi»c«/mi»«/msub»«mn»4«/mn»«/msub»«mo»+«/mo»«msub»«mn»12«/mn»«msub»«mi»c«/mi»«mn»3«/mn»«/msub»«/msub»«/math»
A.
B.
C.
D.
5.  0! is a symbol equal to
A.
B.
C.
D.
6.  «math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«msub»«mn»4«/mn»«msub»«mi mathvariant=¨bold¨»P«/mi»«mn»3«/mn»«/msub»«/msub»«/math» is evaluated as
A.
B.
C.
D.
7.  If the letters word 'Daughter' are to be arranged so that vowels occupy the odd places, then number of different words are
A.
B.
C.
D.
8.  «math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mo»(«/mo»«mi»n«/mi»«mo»-«/mo»«mn»1«/mn»«mo»)«/mo»«msub»«mi»P«/mi»«mi»r«/mi»«/msub»«mo»§nbsp;«/mo»«mo»+«/mo»«mi»r«/mi»«mo».«/mo»«/math»«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mo»(«/mo»«mi»n«/mi»«mo»-«/mo»«mn»1«/mn»«mo»)«/mo»«msub»«mi»P«/mi»«mrow»«mo»(«/mo»«mi»r«/mi»«mo»-«/mo»«mn»1«/mn»«mo»)«/mo»«/mrow»«/msub»«/math» is equal to Options: A.«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«msub»«msub»«mi»n«/mi»«mi»c«/mi»«/msub»«mi»r«/mi»«/msub»«/math» B.«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mfrac»«mrow»«mi»n«/mi»«mo»!«/mo»«/mrow»«mrow»«mo»(«/mo»«mi»r«/mi»«mo»!«/mo»«mo»(«/mo»«mi»n«/mi»«mo»-«/mo»«mi»r«/mi»«mo»)«/mo»«mo»!«/mo»«mo»)«/mo»«/mrow»«/mfrac»«/math» C.«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«msub»«msub»«mi»n«/mi»«mi»p«/mi»«/msub»«mi»r«/mi»«/msub»«/math» D.None of these
A.
B.
C.
D.
9.  The number of ways in which the letters of the word MOBILE be arranged so that consonants always occupy the odd places is
A.
B.
C.
D.
10.  The number of ways in which 15 mangoes can be equally divided among 3 students is Options: A.«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mfrac»«mrow»«mn»15«/mn»«mo»!«/mo»«/mrow»«mrow»«mo»(«/mo»«mn»5«/mn»«msup»«mo»)«/mo»«mn»4«/mn»«/msup»«mo»!«/mo»«/mrow»«/mfrac»«/math» B.«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mfrac»«mrow»«mn»15«/mn»«mo»!«/mo»«/mrow»«mrow»«mo»(«/mo»«mn»5«/mn»«msup»«mo»)«/mo»«mn»3«/mn»«/msup»«mo»!«/mo»«/mrow»«/mfrac»«/math» C.«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mfrac»«mrow»«mn»15«/mn»«mo»!«/mo»«/mrow»«mrow»«mo»(«/mo»«mn»5«/mn»«msup»«mo»)«/mo»«mn»2«/mn»«/msup»«mo»!«/mo»«/mrow»«/mfrac»«/math» D.None of these
A.
B.
C.
D.
11.  If  «math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«msub»«msub»«mi»n«/mi»«mi»p«/mi»«/msub»«mrow»«mi»r«/mi»«mo»§nbsp;«/mo»«mo»§nbsp;«/mo»«/mrow»«/msub»«/math»=336 and «math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«msub»«msub»«mi»n«/mi»«mi»c«/mi»«/msub»«mi»r«/mi»«/msub»«/math»=56,then n and r  will be
A.
B.
C.
D.
12.  The number of ways a person can contribute to a fund out of 1 ten-rupee note, 1 five- rupee note, 1 two-rupee and 1 one rupee note is
A.
B.
C.
D.
13.  «math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«msub»«mi»n«/mi»«msub»«mi»C«/mi»«mn»1«/mn»«/msub»«/msub»«mo»+«/mo»«msub»«mi»n«/mi»«msub»«mi»c«/mi»«mn»2«/mn»«/msub»«/msub»«mo»+«/mo»«msub»«mi»n«/mi»«msub»«mi»c«/mi»«mn»3«/mn»«/msub»«/msub»«mo»+«/mo»«msub»«mi»n«/mi»«msub»«mi»c«/mi»«mn»4«/mn»«/msub»«/msub»«mo»+«/mo»«mo».«/mo»«mo».«/mo»«mo».«/mo»«mo».«/mo»«mo».«/mo»«mo».«/mo»«mo».«/mo»«mo».«/mo»«mo».«/mo»«mo».«/mo»«mo»+«/mo»«mi»e«/mi»«mi»q«/mi»«mi»u«/mi»«mi»a«/mi»«mi»l«/mi»«mi»s«/mi»«/math» Options: A.«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«msup»«mn»2«/mn»«mi»n«/mi»«/msup»«mo»-«/mo»«mn»1«/mn»«/math» B.«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«msup»«mn»2«/mn»«mi»n«/mi»«/msup»«/math» C.«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«msup»«mn»2«/mn»«mi»n«/mi»«/msup»«mo»+«/mo»«mn»1«/mn»«/math» D.None of these
A.
B.
C.
D.
14.  The total number of 9 digits numbers of different digits is
A.
B.
C.
D.
15.  The value of «math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«munderover»«mrow»«mo»§#8721;«/mo»«mi»r«/mi»«mo».«/mo»«/mrow»«mrow»«mi»r«/mi»«mo»=«/mo»«mn»1«/mn»«/mrow»«mn»10«/mn»«/munderover»«/math»«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«msub»«mi»r«/mi»«msub»«mi»p«/mi»«mi»r«/mi»«/msub»«/msub»«/math» Options: A.«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«msub»«msub»«mn»11«/mn»«mi»P«/mi»«/msub»«mn»11«/mn»«/msub»«/math» B.«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«msub»«msub»«mn»11«/mn»«mi»P«/mi»«/msub»«mn»11«/mn»«/msub»«/math»-1 C.«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«msub»«msub»«mn»11«/mn»«mi»P«/mi»«/msub»«mn»11«/mn»«/msub»«/math»+1 D.None of these
A.
B.
C.
D.
16.  The number of different words that can be formed with 12 consonants and 5 vowels by taking 4 consonants and 3 vowels in each word is Options: A.«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«msub»«msub»«mn»12«/mn»«mi»c«/mi»«/msub»«mn»4«/mn»«/msub»«mo»§#215;«/mo»«msub»«mn»5«/mn»«msub»«mi»c«/mi»«mn»3«/mn»«/msub»«/msub»«/math» B.«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«msub»«msub»«mn»17«/mn»«mi»c«/mi»«/msub»«mn»7«/mn»«/msub»«/math» C.4950«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mo»§#215;«/mo»«/math»(7)! D.None of these
A.
B.
C.
D.
17.  The Supreme Court has given a 6 to 3 decision upholding a lower court; the number of mays it can give a majority decision reversing the lower court is
A.
B.
C.
D.
18.  The number of ways in which 7 boys sit in a round -table so that two particular boys may sit together is
A.
B.
C.
D.
19.  If . nP3: nP2 =3:1, then n is equal to
A.
B.
C.
D.
20.  If n cr-1 = 56, «math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«msub»«msub»«mi»n«/mi»«mi»c«/mi»«/msub»«mi»r«/mi»«/msub»«/math»= 28 and n cr+1 = 8, then r is equal to
A.
B.
C.
D.
Back to top

Removing ad is a premium feature

Upgrade and get a lot more done!
Take Another Quiz